AW: max aggregator dosen't work as expected

Posted by Claudia Wegmann on
URL: http://deprecated-apache-flink-user-mailing-list-archive.369.s1.nabble.com/max-aggregator-dosen-t-work-as-expected-tp8357p8359.html

OK, found my mistake reagarding question 2.). I key by the id value and gave all the data sets different values there. So of course all 4 data sets are printed. Sorry J

But question 1.) still remains.

 

Von: Claudia Wegmann [mailto:[hidden email]]
Gesendet: Montag, 8. August 2016 14:27
An: [hidden email]
Betreff: max aggregator dosen't work as expected

 

Hey,

 

I have some questions to aggregate functions such as max or min. Take the following example:

 

//create Stream with event time where Data contains an ID, a timestamp and a temperature value

DataStream<Data> oneStream = env.fromElements(

        new Data(123, new Date(116, 8,8,11,11,11), 5), 

        new Data(124, new Date(116, 8,8,12,10,11), 8),

        new Data(125, new Date(116, 8,8,12,12,11), 10),

        new Data(126, new Date(116, 8,8,12,15,11), 2))

.assignTimestampsAndWatermarks(new AscendingTimestampExtractor<Data>() {
    @Override
    public long extractAscendingTimestamp(final Data data) {
        return data.getTimestamp().getTime();
    }
});

//calluclate max value of temperature per hour

DataStream<Data> maxStream = WatermarkStream

        .keyBy("id")

        .timeWindow(Time.hours(1))

        .max("temp");
maxStream.print();

Here are the questions I ran into:

1.)    Why does the resulting stream “maxStream” have to be of type Data? From the documentation and the difference to maxBy I would expect the resulting stream to be of type Integer?

2.)    Executing the code as it is above, I would expect the printed result be the data with ID 124 and ID 125. However, the execution prints all 4 data sets. Did I totally get this example wrong? How would the code need  to look, to get the expected result?

3.)    Can you point me to a good example for using time windows and aggregates? I couldn’t find one that explains the above questions.

 

Thanks for your help and best wishes,

Claudia