With a checkpointed RocksDB based state backend, can I expect the registered processing timers to be fault tolerant? (along with the managed keyed state).
Example - A task manager instance owns the key k1 (from a keyed stream) that has registered a processing timer with a timestamp thats a day ahead in the future. If this instance is killed, and the key is moved to another instance, will the onTimer trigger correctly on the other machine at the expected time with the same keyed state (for k1)? Thanks, Moiz |
Yes, registered timers are stored in managed keyed state and should be fault-tolerant. -Eron On Thu, May 25, 2017 at 9:28 AM, Moiz S Jinia <[hidden email]> wrote:
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Hi Moiz! Adding a bit of more detail here: Yes, the timer will be restored on whatever new instance is responsible for that key. There is one “gotcha” to look out for, though: the firing time of timers are absolute; what this means is that if the checkpoints timer’s firing processing timestamp is t (which is basically the registering time + configured trigger time), then it will fire also at processing timestamp t on the new instance. Therefore, you should be aware of out-of-sync clocks between the 2 instances. Cheers, Gordon
On 26 May 2017 at 12:44:00 AM, Eron Wright ([hidden email]) wrote:
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In reply to this post by Eron Wright
Awesome. Thanks. On Thu, May 25, 2017 at 10:13 PM, Eron Wright <[hidden email]> wrote:
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A follow on question. Since the registered timers are part of the managed key state, do the timers get cancelled when i call state.clear()? Moiz On Thu, May 25, 2017 at 10:20 PM, Moiz S Jinia <[hidden email]> wrote:
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Hi Moiz,
state.clear() refers to the state that you have registered in your job, using the getState() from the runtimeContext. Timers are managed by Flink’s timer service and they are cleaned up by Flink itself when the job terminates. Kostas
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Thanks Kostas. So even though the timer state is managed separately from the key state (from runtimeContext) I can safely assume both the states to be fault tolerant and maintain association with the key of the stream? On Fri, May 26, 2017 at 1:51 PM, Kostas Kloudas <[hidden email]> wrote:
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Yes, that is correct.
Kostas
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